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Pembahasan soal
Bilangan Kuantum



Soal:

Tentukan nilai keempat bilangan kuantum (n, l, m, dan s) untuk elektron terakhir pada atom:


Penyelesaian:


4Be

[He] 2s2
  • Bilangan kuantum utama (n) = 2
  • Bilangan kuantum azimuth (l) = 0
  • Bilangan kuantum magnetik (m) = 0
  • Bilangan kuantum spin (s) = - ½

12Mg

[Ne] 3s2
  • Bilangan kuantum utama (n) = 3
  • Bilangan kuantum azimuth (l) = 0
  • Bilangan kuantum magnetik (m) = 0
  • Bilangan kuantum spin (s) = - ½

18Ar

[Ne] 3s2 3p6
  • Bilangan kuantum utama (n) = 3
  • Bilangan kuantum azimuth (l) = 1
  • Bilangan kuantum magnetik (m) = + 1
  • Bilangan kuantum spin (s) = - ½

20Ca

[Ar] 4s2
  • Bilangan kuantum utama (n) = 4
  • Bilangan kuantum azimuth (l) = 0
  • Bilangan kuantum magnetik (m) = 0
  • Bilangan kuantum spin (s) = - ½





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open your mind, you will be confused
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